Question

solve 5x^2-3x=(7x^2+5x)-(2x^2+16)

Answer 1

combine like terms,
whats 7x^2-2x^2 on right side ?

Answer 2

5x

Answer 3

5x or 5x^2 ?

Answer 4

5x^2

Answer 5

yes,
now bring that 5x^2 on left side, you know how ?

Answer 6

subtraction?

Answer 7

correct!

Answer 8

\[5x ^{2}-3x=7x ^{2}+5x-2x ^{2}-16\]

Answer 9

so it becomes \[8x=16\] and x=2

Answer 10

so, what will u get after subtracting 5x^2 on both sides ?

Answer 11

so the answer is -2 ?

Answer 12

-2 ? how u got that ?

Answer 13

because when i subtract -5x from the left side which was -5x-3x it gave me only -3x on the left side. then on the right side i was left with 5x+16

Answer 14

then i subtracted 5x and subtracted it from -3x

Answer 15

actually on right side, it'll be 5x-16
because (7x^2+5x)-(2x^2+16) = 5x^2 +5x -16

Answer 16

u have to subtract 5x from both sides so u will get -8x=-16

Answer 17

therefore x=2

Answer 18

then as per what you wrote, i am sure you got
-8x on left
-8x = -16 will actually give u x=2
got this ?