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Which system of inequalities has no solution? Answer y > -1/2x + 3 y > -1/2x – 1 y > -1/2x + 3 y < -1/2x – 1 y < -1/2x + 3 y > -1/2x – 1 y < -1/2x + 3 y < -1/2x – 1
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The 2nd one ! The system is : \[y > -\frac12x + 3\\ y < -\frac12x – 1\] Then : by multiplying the 1st inequality by -1 we get : \[ -y<+\frac12-3\\ y < -\frac12x – 1 \] By adding the two inequality we get : \[ 0<-4 \] which is impossible !
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