Question

Help please!! Much Appreciated! (:

Solve each system by any method of your choice:

2x-6y=16
3x+18y=-30

Answer 1

multiply top equation by 3 .... this way you can eliminate "y"

6x -18y = 48
3x +18y = -30
--------------
9x +0 = 18

--> x = 2

plug x=2 into either equation to solve for y

Answer 2

So:
3x+18(2)=-30
3x+36=-30
-36 -36
3x=-6
= -2

Answer 3

haha not quite just you just happened to get the right answer

Answer 4

3(2) +18y = -30
6 +18y = -30
-6 -6
-------------
18y = -36
y = -2

Answer 5

haha(: well that's weird :P ...so how would you do it?

Answer 6

Above method is called elimination method.
Here is substitution method:

1) From equation 6x-18y=48 we can deduce x=(48+18y)/6 that will be x=8+3y
Now u can substitute the value of x=8+3y in second equation (i.e 3x+18y=-30)

2) On substitution 3(8+3y)+18y=-30
=>24+9y+18y=-30
=>27y=-54
=>y=-2

3)Now by substuting y in anu of the equation u can get the value of x

Answer 7

cutie less than 3 ?
okay.

Answer 8

Okay, that's how I was doing it at first then got mixed up.
Thanks! I really appreciate all of your guy's help!! GBU!!! :)

@primeralph Do you mean the answer is less than 3?

Answer 9

No, your name says cutie less than 3.

Answer 10

Oh, haha! @primeralph very funny:P