1. Solve √3(x - 2) + 7 = 28

2.What is the equation of the line that passes through the point (4, 1) and is perpendicular to the line y = –2x + 4?

Question

1. Solve √3(x - 2) + 7 = 28

2.What is the equation of the line that passes through the point (4, 1) and is perpendicular to the line y = –2x + 4?

bahrom7893 · Answer

is the whole thing under sqrt, or is it just the 3?

anonymous · Answer

(x - 2) is also under it but not the rest

bahrom7893 · Answer

okay so first, simplify a little:
sqrt(3(x+2)) = 28-7 = 21
sqrt(3(x+2)) = 21
square both sides:
3(x+2) = 21^2

bahrom7893 · Answer

can u take it up from here?

anonymous · Answer

yes thank you what about the second question..

bahrom7893 · Answer

Perpendicular means the slope is -1/original slope

bahrom7893 · Answer

So your new slope = -1/(-2) = 1/2

bahrom7893 · Answer

The equation is of the form
y = mx + b
Plug in the values that we found, and the ones they gave us:
1 = (1/2) * 4 + b
solve for b, and you'll end up with the answer.

bahrom7893 · Answer

Well the equation will be:
y = (1/2)x + b, whatever b is