Information for question 1-2. One-half of the students at Greendale Middle School take art. Two-thirds of students take Spanish. Jenny uses a coin and a standard number cube as a simulation of the students at Greendale Middle School. Jenny let's "T" represent a student taking art and "H" represents a student not taking art. She lets the numbers 1 2 3 and 4 on the number cube represent a student taking Spanish and the numbers 5 and 6 represent a student not taking Spanish. This is the table: http://gyazo.com/cb9fd2a2f5ff44a80f719e025b7abd69
Find the probability that a student a Greendale middle school takes both art and spanish 3/20 2/5 7/20 1/10
Find the probability that a student a Greendale middle school takes neither art nor spanish 3/20 2/5 7/20 1/10
Are these the alternatives?
So there are 20 students. the students marked as T take art and the ones with 1,2,3,4 take spanish, that means that the students marked with T 1,2,3 or 4 take both
On the table we find 7 marked as such
So the probability for that is 7/20
For the second one, the students who take neither are marked with H 5 or 6, on the table we find 2 marked as such
so the probability for that is 2/20, which simplifies to 1/10
ok thank you so much:D
Anytime mate :)
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