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Mathematics 21 Online
OpenStudy (vane11):

Help Please! =/ Find the number z such that the proportion of observations that are less than z in a standard Normal distribution is 0.7. Mark your choice below.

OpenStudy (vane11):

what number did you look up on the table to get .525?

OpenStudy (dumbcow):

0.7 which represents area under curve

OpenStudy (dumbcow):

its not exact since table only uses z values to 2 decimal places

OpenStudy (dumbcow):

if you want a more exact answer, type this formula into Excel: 'NORMSINV(0.7)"

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