Question

the sum of three consecutive numbers is less than or equal to 216. find the greatest possible values of these integers

Answer 1

let x be the first number

so x+1 is the next number

x+2 is the next one after that

Answer 2

the sum of three consecutive numbers ---> (x)+(x+1)+(x+2) ---> 3x + 3

Answer 3

so...

the sum of three consecutive numbers is less than or equal to 216

translates to

3x + 3 <= 216

Answer 4

solve for x and tell me what you get

Answer 5

i got 71 @jim_thompson5910

Answer 6

x <= 71 is correct

so 71 is the largest value x can be

Answer 7

which means

x+2 = 71+2 = 73 is the largest value possible

Answer 8

so would i write 71 down or 73 as my answer @jim_thompson5910

Answer 9

73 since that's the larger of the two

Answer 10

actually I think they want all 3, so

71, 72, 73

Answer 11

they want the "greatest possible values of these integers"

so you're listing them all (the largest they can be)

Answer 12

ok thanks ... can you help with this one
the sum of three consecutive odd numbers is more than 207. find the minimum values of these integers @jim_thompson5910

Answer 13

the sum of three consecutive odd numbers is more than 207

translates to

(2x+1)+(2x+3)+(2x+5) > 207

solve for x

Answer 14

i got 33 @jim_thompson5910

Answer 15

x > 33, yep

Answer 16

now plug in x = 34 (the next integer after 33)

2x+1 = 2*34+1 = 69

2x+3 = 2*34+3 = 71

2x+5 = 2*34+5 = 73

Answer 17

so the smallest 3 integers are: 69, 71, 73