Question

Solve the equation by using the quadratic formula:

Answer 1

\[x^2+4x+3=0\]

Answer 2

\[x=\frac{ -4 \pm \sqrt{4^2-4*3}}{ 2 }\]\[x=\frac{ -4\pm \sqrt{4} }{ 2 }\]\[x=\frac{ -4\pm2 }{ 2 }\]\[x _{1}=\frac{ -4+2 }{ 2 } = \frac{ -2 }{ 2 } = -1\]\[x _{2}=\frac{ -4-2 }{ 2 }=\frac{ -6 }{ 2 } = -3\]

Answer 3

so:
-1,-3 ??

Answer 4

Yep!

Answer 5

haha(: thanks!! Much appreciated! GBU!! :)