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the indefinite integral of 1/(sqrt4+x^2)
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Let \(x=2\tan u\), so \(dx=2\sec^2u~du\).
then what do i do
\[\int\frac{2\sec^2u}{\sqrt{4+(2\tan u)^2}}~du\\ \int\frac{2\sec^2u}{\sqrt{4+4\tan ^2u}}~du\\ \int\frac{2\sec^2u}{\sqrt4\sqrt{1+\tan ^2u}}~du\\ \int\frac{\sec^2u}{\sqrt{1+\tan ^2u}}~du\] What's \(1+\tan^2u\) equal to?
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