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Mathematics 10 Online
OpenStudy (anonymous):

factor 75a^2(x-2)-12(x-2)

OpenStudy (anonymous):

Put (x-2) in evidence, you will have: (x-2)(75a^2-12) Put 3 in evidence in the second factor, 3(x-2)(25a^2-4)

OpenStudy (whpalmer4):

\[75a^2(x-2)-12(x-2)\]Factor the \((x-2)\) out of both terms: \[(x-2)(75a^2-12)\]Now factor a 3 out of the 2nd product term:\[3(x-2)(25a^2-4)\]Now recognize that the final product term is a difference of squares:\[3(x-2)(5a-2)(5a+2)\]

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