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Algebra
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1.(2x2 – 23x + 63) ÷ (x – 7) (1 point) This is what i got so far. use synthetic division to solve -7) 2 -23 +63 -14 2
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you made a common mistake
-7) 2 -23 +63 -14 2
what did i do wrong ?
since you are dividing by \(x-7\) you should put a \(7\) on the side, not a \(-7\)
2 -23 63 7 14 -------------------------- 2 -9
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etc one more step and you are done
7) 2 -23 +63 14 -63 2 -9 0
that is right
so is it 2x-9?
yes
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Thankyou very much (: !
meaning \[2x^2-23x+63=(x-7)(2x-9)\] and no remainder yw
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