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okay so convert the following numbers in base 10 to numbers in other bases as indicated: convert 345 in base 10 to an equivalent number in base 4!
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so i divided 345 by 4 and got 86.25 but how do you get the remainder
\[345_{10}=3\times10^2+4\times10^1+5\times10^0\]
\[345_{4}=a\times4^4+ b\times4^3+c\times4^2+d\times4^1+e\times4^0\]
\[345/4^4=345/256=1+89/256\] so \(a=1\) \[89/4^3=89/64=1+25/64\] so \(b=1\) \[25/4^2=25/16=1+9/64\] so \(c=1\) \[9/4^1=9/4=2+1/4\] so \(d=2\) \[1/4^0=1/1=1\] so \(d=1\)
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