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I need Algebra 2 help please have a final tomorrow and I am stuck on this question. Nine qualified applicants apply for a part-time job. If the manager randomly hires 3 of them, what is the probability that he hires the 3 oldest?
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There is only one way to hire the 3 oldest (if you can only hire 3 total) this is out of 9 C 3 = (9!)/(3!*(9-3)!) = 84 ways total to hire 3 people (from a pool of 9 applicants)
so the probability is 1/84
Thank you for helping me but can you explain a little more
I'm using the combination formula which is n C r = (n!)/(r!*(n-r)!)
ok got thanks
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a more in depth explanation is given here http://www.mathsisfun.com/combinatorics/combinations-permutations.html
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