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Mathematics 14 Online
OpenStudy (anonymous):

Find the slant height x of the pyramid shown, to the nearest tenth.

OpenStudy (anonymous):

OpenStudy (anonymous):

@jim_thompson5910 Isn't it 5.7?

jimthompson5910 (jim_thompson5910):

close, but no

OpenStudy (anonymous):

wait..Lol. 5.3?

jimthompson5910 (jim_thompson5910):

|dw:1370925778466:dw|

jimthompson5910 (jim_thompson5910):

better, x = 5.3

jimthompson5910 (jim_thompson5910):

|dw:1370925806568:dw|

OpenStudy (anonymous):

Is this one 19?

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

hellllllllllloooooooooooooo?

OpenStudy (anonymous):

Use Pythagorean theorem again

OpenStudy (anonymous):

I am asking if it's 19~!

jimthompson5910 (jim_thompson5910):

close

OpenStudy (anonymous):

20?

OpenStudy (anonymous):

You need to go into decmals again

OpenStudy (anonymous):

I'm asking jim..

OpenStudy (anonymous):

WOW BYE

jimthompson5910 (jim_thompson5910):

you need to solve 11^2 + 16^2 = x^2 for x

jimthompson5910 (jim_thompson5910):

and anyone is allowed to help or pitch in if they want

OpenStudy (anonymous):

Uhhh..I got 142, 129

jimthompson5910 (jim_thompson5910):

11^2 + 16^2 = x^2 121 + 256 = x^2 x^2 = 377 x = ??

OpenStudy (anonymous):

.......I already told you what I got?

OpenStudy (anonymous):

next, I put 377^2

jimthompson5910 (jim_thompson5910):

you take the square root of that

OpenStudy (anonymous):

Oh... my gosh. I already did that.

jimthompson5910 (jim_thompson5910):

and you got?

OpenStudy (anonymous):

142, 129

jimthompson5910 (jim_thompson5910):

that's not correct

OpenStudy (anonymous):

Exactly.

jimthompson5910 (jim_thompson5910):

square root, not square

jimthompson5910 (jim_thompson5910):

look for the square root button

OpenStudy (anonymous):

Now I got 533.15

jimthompson5910 (jim_thompson5910):

sqrt(377) = 19.4164878389476 make sure you round that accordingly

OpenStudy (anonymous):

I think it's 19.

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