Mathematics
14 Online
OpenStudy (anonymous):
Find the slant height x of the pyramid shown, to the nearest tenth.
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OpenStudy (anonymous):
OpenStudy (anonymous):
@jim_thompson5910 Isn't it 5.7?
jimthompson5910 (jim_thompson5910):
close, but no
OpenStudy (anonymous):
wait..Lol. 5.3?
jimthompson5910 (jim_thompson5910):
|dw:1370925778466:dw|
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jimthompson5910 (jim_thompson5910):
better, x = 5.3
jimthompson5910 (jim_thompson5910):
|dw:1370925806568:dw|
OpenStudy (anonymous):
Is this one 19?
OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (anonymous):
hellllllllllloooooooooooooo?
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OpenStudy (anonymous):
Use Pythagorean theorem again
OpenStudy (anonymous):
I am asking if it's 19~!
jimthompson5910 (jim_thompson5910):
close
OpenStudy (anonymous):
20?
OpenStudy (anonymous):
You need to go into decmals again
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OpenStudy (anonymous):
I'm asking jim..
OpenStudy (anonymous):
WOW BYE
jimthompson5910 (jim_thompson5910):
you need to solve
11^2 + 16^2 = x^2
for x
jimthompson5910 (jim_thompson5910):
and anyone is allowed to help or pitch in if they want
OpenStudy (anonymous):
Uhhh..I got 142, 129
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jimthompson5910 (jim_thompson5910):
11^2 + 16^2 = x^2
121 + 256 = x^2
x^2 = 377
x = ??
OpenStudy (anonymous):
.......I already told you what I got?
OpenStudy (anonymous):
next, I put 377^2
jimthompson5910 (jim_thompson5910):
you take the square root of that
OpenStudy (anonymous):
Oh... my gosh. I already did that.
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jimthompson5910 (jim_thompson5910):
and you got?
OpenStudy (anonymous):
142, 129
jimthompson5910 (jim_thompson5910):
that's not correct
OpenStudy (anonymous):
Exactly.
jimthompson5910 (jim_thompson5910):
square root, not square
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jimthompson5910 (jim_thompson5910):
look for the square root button
OpenStudy (anonymous):
Now I got 533.15
jimthompson5910 (jim_thompson5910):
sqrt(377) = 19.4164878389476
make sure you round that accordingly
OpenStudy (anonymous):
I think it's 19.