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Mathematics 20 Online
OpenStudy (anonymous):

COMBINATION: From a pack of 52 cards, how many different groups of three spades can be chosen?

OpenStudy (anonymous):

permutation or combination? i'm going to assume combination

OpenStudy (anonymous):

So how to do?

OpenStudy (anonymous):

\[\frac{ n! }{k!(n-k)! }\] this is the formula for finding the number of combinations, where n is 13 (number of spades and k is 3 (the number of spades you're choosing)

OpenStudy (anonymous):

286 ways i believe

OpenStudy (anonymous):

Thanks :)

OpenStudy (anonymous):

you're welcome

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