Question

Find relative extrema at Sin^2 x

0 12 years ago

Answer 1

IS THIS A YR 12 Q'?

Answer 2

f(x) = sin^2 x
f'(x) = 2 sinx cos x = sin(2x)

f'(x) = 0
sin(2x) = 0
x = ...

Test if it is a max/min by drawing a table / second derivative test.