Question

Find the center of the circle with equation x^2+y^2-10x+6y+27=0

Answer 1

You gotta put it in this form
\[(x-h)^2+(y-k)^2=r^2\]
Try using completing the square
\[ [x^2-10x]+[y^2+6y]+27=0\]

Answer 2

Then h and k is the center