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A jar contains 14 nickels, 10 dimes, 6 quarters, and 22 pennies. A coin is chosen at random from the jar. What is the probability that the coin chosen is a dime?
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This would mean you take the number of the thing you want (10 dimes so 10) and put it OVER the total amount of possible things to get...so 14 + 10 + 6 + 22 = 52 so we have 10 -- 52 can this be simplified at all...?
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