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2[3(2x-1) +7] =
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\[\huge 2[3(2x-1)+7]\] first solve, \[\huge 3(2x-1)+7\]
wht happened to the 2 we don't use it yet right?
we use 2 at last
kk
so solve it \(\large 3(2x-1)+7\)
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does it go like this 2+ 6x -3 +7
no!!!
then its comes up to 6x +6
darn it
okay first does it start like this (6x -3) +7
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hello
ok anyone else
2[3(2x-1) +7] =2[6x-3+7] =2[6x+4] =12x+8
Thank you so much :)
@bbb911 sorry!!! my internet is very slow
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its kk
so can i help you??
U r WELCOME . @bbb911
yes imma ask another in a minute
oh!!! kk ,.. i missed a chance
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