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Mathematics 12 Online
OpenStudy (anonymous):

a vector.

OpenStudy (john_es):

I think 50 degrees. Maybe you are trying to find the angle with the z-axis (not x-axis), and then \[\cos^2\theta=1-\cos^2(79)-\cos^2(42)=0.6413\] Then, \[\arccos(0.6413)\approx50^o\]

OpenStudy (anonymous):

thank you

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