Question

Use fundamental properties to simplify

Secx cscx -tanx

Answer 1

\[\frac{1}{\cos x}\frac{1}{\sin x}-\frac{\sin x}{\cos x}=\]
\[=\frac{1-\sin^2x}{\sin x\cos x}=\frac{\cos^x}{\sin x\cos x}=\frac{\cos x}{\sin x}=cotan x \]

Answer 2

It should be,
\[\frac{1-\sin^2x}{\sin x \cos x}=\frac{\cos^2 x}{\sin x\cos x}=\frac{\cos x}{\sin x}=cotan x\]