Question

CAN SOMEONE PPPLLLZZZ HELP ME!!!!!!
what is the value of √9y^4+12√y^6-3√y^6-√y^4

A. 8y^2+9y^3
B. 11y^2
C. 11y^5
D. 2y^2+9y^3

Answer 1

\[\sqrt{9y ^{4}}=3y ^{2}\]
\[12\sqrt{y ^{6}}=12y ^{3}\]
\[-3\sqrt{y ^{6}}=-3y ^{3}\]
\[-\sqrt{y ^{4}}=-y ^{2}\]

add them

Answer 2

so it would be 11y^5

Answer 3

no!! 2y^2+9y^3 :)

Answer 4

but that doesnt make sense if u added -√4^4 and -y^2 how do u get that????

Answer 5

i don't understand what you asked

Answer 6

how did you get that answer

Answer 7

3y^2-y^2=2y^2 and 12y^3-3y^3=9y^3
so answer is 2y^2+9y^3