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Precalculus
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Help with derivatives!
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gimmeee
\[\LARGE f(x)=(x+1) \tan^{-1}(e)^{-2x},then ~f'(0)=?\]
no
wala wala luigi is here
I am getting \[\Huge \frac{\pi}{4}-1\] but its wrong...
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d/dx of tan-1 = ?
1/1+x^2
I took the derivative right I used product rule,please first solve yourself and see if you can get the answer right then proceed with the explanation.
well i need to know if im reading the question right
question is right,its e^-2x
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tan-1 (e^2x) or (tan-1 e)^-2x ??
tan-1 (e^-2x)*
\[\Huge \tan^{-1}(e^{-2x})\]
|dw:1371059538129:dw|
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