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Precalculus 8 Online
OpenStudy (dls):

Help with derivatives!

OpenStudy (dan815):

gimmeee

OpenStudy (dls):

\[\LARGE f(x)=(x+1) \tan^{-1}(e)^{-2x},then ~f'(0)=?\]

OpenStudy (luigi0210):

no

OpenStudy (dan815):

wala wala luigi is here

OpenStudy (dls):

I am getting \[\Huge \frac{\pi}{4}-1\] but its wrong...

OpenStudy (dan815):

d/dx of tan-1 = ?

OpenStudy (dls):

1/1+x^2

OpenStudy (dls):

I took the derivative right I used product rule,please first solve yourself and see if you can get the answer right then proceed with the explanation.

OpenStudy (dan815):

well i need to know if im reading the question right

OpenStudy (dls):

question is right,its e^-2x

OpenStudy (dan815):

tan-1 (e^2x) or (tan-1 e)^-2x ??

OpenStudy (dan815):

tan-1 (e^-2x)*

OpenStudy (dls):

\[\Huge \tan^{-1}(e^{-2x})\]

OpenStudy (dan815):

|dw:1371059538129:dw|

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