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The time required to finish a test is normally distributed with a mean of 60 minutes and a standard deviation of 10 minutes. What is the z-Score for a student who finishes the test in 45 minutes?
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theres a nice compact formula for this\[z=\frac{x-mean}{sd}\]
still confused.
well, they are asking for z, they give you x, mean, and sd .... the rest us just plugging in the specifics for x, mean, and sd
sd is standard deviation or student?
standard deviation
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so it would be x-60/10?
(x-60)/10 yes, now fill in for x
45-60/10?
correct
ok so -15/10 = -1.5?
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thatll do it
thanks so much!
youre welcome
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