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Mathematics 7 Online
OpenStudy (anonymous):

solve over 0

jimthompson5910 (jim_thompson5910):

Hint: sin^2 = 1-cos^2

OpenStudy (anonymous):

with the 2 would it become 2-2cos^2x on the left?

jimthompson5910 (jim_thompson5910):

correct

jimthompson5910 (jim_thompson5910):

you now have this 2-2cos^2x = 3cosx+3

jimthompson5910 (jim_thompson5910):

if you let u = cos x, then u^2 = cos^2x

jimthompson5910 (jim_thompson5910):

giving you 2 - 2u^2 = 3u + 3

jimthompson5910 (jim_thompson5910):

solve that for u, then use those solutions to find the solutions for x

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