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OpenStudy (anonymous):
what is the simplified form of 4x^2-25/2x+5
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OpenStudy (jim766):
note the numerator is a difference of 2 squares
OpenStudy (callisto):
Factorize the numerator using the identity \(a^2 -b^2 = (a+b)(a-b)\), then cancel the common factor.
OpenStudy (jim766):
if you know what that is, makes it easier to factor
OpenStudy (anonymous):
okk. then ?
OpenStudy (jim766):
then cancel out
what is 4x^2 - 25 factored
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OpenStudy (anonymous):
(2x-5)(2x+5).. ?
OpenStudy (jim766):
right, now
(2x + 5)(2x -5) / 2x + 5 what is left after you cancel out 2x + 5
OpenStudy (anonymous):
(2x-5) . ii know that . but how do i find the restrictions.?
OpenStudy (jim766):
keep in mind the fractions are undefined when the denominator = 0
so we need to ask ourself what would make
2x + 5 = 0 , just solve it
OpenStudy (anonymous):
2x+5=0
2x=-5
x= -5/2
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OpenStudy (jim766):
right, the only time that this cant be done is when x = -5/2 or -2.5
make sense?
OpenStudy (anonymous):
ohh okk ii get it. thankyou. youve been a great help !!!!! (:
OpenStudy (jim766):
yw
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