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y varies jointly with x and the square of n. When y = 25, x = 3 and n = 4. Find the value of y when x = 5 and n = 10. Round to the nearest whole number.
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If y varies jointly with x and the square of n, that means \[y = kxn^2\] where \(k\) is a constant. Plug in the known values of \(x,y, n\) to find the value of \(k\). Then plug that value of \(k\) into the formula to find \(y\) when \(x=5, n = 10\).
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