Question

y varies jointly with x and the square of n. When y = 25, x = 3 and n = 4. Find the value of y when x = 5 and n = 10. Round to the nearest whole number.

Answer 1

If y varies jointly with x and the square of n, that means

\[y = kxn^2\] where \(k\) is a constant.
Plug in the known values of \(x,y, n\) to find the value of \(k\). Then plug that value of \(k\) into the formula to find \(y\) when \(x=5, n = 10\).

Answer 2

Thanks, I understand now.

Answer 3

what do you get for your answer?