Question

What are the minimum, first quartile, median, third quartile and maximum of the data set? 60,50,130,200,180,150,100,140
answer choices are
A: min-50, 1Q-80, Median-135, 3Q-165, Max-200
B: min-50, 1Q-107.5, Med-150, 3Q-182.5, Max-200
C: min-50, 1Q-80, Med-135, 3Q- 182.5, Max-200<---my answer choice
D: Min-50, 1Q-65, Med-150, 3Q-165, Max-200
before this I solved it on my paper my answers were:
Min-50
1Q-60
Med-135
3Q-180
Max-200

Answer 1

put the numbers in numerical order...
50,60,100,130,140,150,180,200
median (middle number) = (140 + 130)/2 = 270/2 = 135
first quartile -- (60 + 100)/2 = 160/2 = 80
third quartile -- (150 + 180)/2 = 330/2 = 165
minimum -- 50
maximum -- 200
I got the answer as A.

Answer 2

Oh I see how you did it, I guess I did wrong, Thank you for explaining I don't look forward for answer I would want to learn how to do it. Thanks again ;)

Answer 3

your quite welcome.....they can sometimes be a little confusing :)

Answer 4

oh yes they can.