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A regular octagon has side length 10.9 in. The perimeter of the octagon is 87.2 in and the area is 392.4 in2. A second octagon has side lengths equal to 16.35 in. Find the area of the second octagon.
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(2+2√2)a^2 where a is a side. (2+2√2)16.35in^2 choose rounding
Im so confused,
@VickyTheMathlete , you there. How do I use that formula
do ( two plus (2 times the square root of two)) then multiply it by the length of one side of the octagon squared.
80.58?
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