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Simplify: (1+cot^2y)(cos2y + 1) The first cot is squared, the second is not. Thanks!
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the second one is cot or cos?
\[(1+cot^2y)(cos2y+1)\]or \[(1+cot^2y)(cot2y+1)\]
the second one is cos
\[1+cot^2y = \frac{1}{sin^2y}\] \[cos2y+1=2cos^2y\] ---------------------------- time them together to get \[\frac{2cos^2y}{sin^2y}=2cot^2y\]
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