Question

need help with this equation 4^2x=32?

Answer 1

http://openstudy.com/users/raevenbennett#/updates/51b8b872e4b0862d0498c5c5

Answer 2

~~~~~~~~~~~~~LS~~~~~~~~~~~~~~~~~
\[4^{2x} \]\[= (2^2)^{2x}\]\[=2^{4x}\]
~~~~~~~~~~~~~RS~~~~~~~~~~~~~~~~~
\[32\]\[=2^5\]
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
So,
\[4^{2x} = 32\]\[2^{4x}=2^5\]Can you solve it now?

Answer 3

so it'll be 4x=5 right then that'll be 4/5

Answer 4

@Callisto