Question

A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = - 16t^2 + 576t. After how many seconds does the projectile take to reach its maximum height? Show your work for full credit.

Answer 1

dh/dt = velocity = -32t +576
dh/dt = 0 at top, she it starts falling back down
-32t+576 = 0
t = 576/32 = 18s

check height = -16*18*18 + 576*18 = 5,185m

Answer 2

Thanks!!!