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simplify the expression 0.11y cubed + 0.6y cubed - .05y cubed.
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just simplify the question there all like terms
I came up with 0.092y
and sorry the last one was suppose to be 0.5y cubed
i got 1.31y
\[0.1y{3}+0.6y ^{3}-0.5y ^{3}\]
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0.11+0.6-0.05 = 0.71-0.05 = 0.66 Hence , 0.66y cube
i tried
0.1y+0.6y=0.7y 0.7y-0.5y=0.2y so would it be \[0.2y^{3}\]
actually yea it would
ok thank you and sorry I had the numbers all mixed up
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np
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