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OpenStudy (anonymous):
Pleas help!!!! For the following chemical reaction, how many moles of lead(II) iodide (PbI2) will be produced from 4 mol of potassium iodide (KI)? 2KI+Pb(NO3)2=PbI2+ 2KNO3
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OpenStudy (abb0t):
Divide 4 by 2
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