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Mathematics 12 Online
OpenStudy (anonymous):

CAN SOMEONE PLLZZZZ HELP!!!!!!!!!! 1. add and simplify (x/8x)+(7x-8/8x) 2. add and simplify (4/x-7)+(1/x-3)

OpenStudy (ivettef365):

the first problem you have x 7x - 8 ------ + -------- 8x 8x

OpenStudy (ivettef365):

whta is the common denominator

OpenStudy (anonymous):

8x

OpenStudy (ivettef365):

ok then you have x + 7x - 8 ---------- 8x

OpenStudy (anonymous):

ok so my answer would be |dw:1371232193752:dw|

OpenStudy (ivettef365):

no you can do that

OpenStudy (ivettef365):

not do that

OpenStudy (ivettef365):

then you have 8x - 8 ------ 8x

OpenStudy (ivettef365):

you can take out the 8 8(x-1) ------ 8x

OpenStudy (ivettef365):

now you can cancel the 8 and you have x - 1 ----- x

OpenStudy (ivettef365):

which is the same as 1 - 1/x

OpenStudy (anonymous):

ohhh ok wb #2

OpenStudy (anonymous):

what would i do ther because they dont have common denominators

OpenStudy (ivettef365):

the second problem you have 4 1 ----- + ------- x-7 x-3

OpenStudy (ivettef365):

What is the common denominator ??

OpenStudy (anonymous):

x?

OpenStudy (ivettef365):

no, actually you have to take the hold thing so the common denominator would be (x-7)(x-3)

OpenStudy (anonymous):

ohh

OpenStudy (ivettef365):

so now what you do is 4 (x-3) + 1 (x-7) --------------- (x-3)(x-7)

OpenStudy (anonymous):

ok then u would have |dw:1371232713526:dw|

OpenStudy (ivettef365):

no, you need to first multiply 4(x-3) and then 1(x-7)

OpenStudy (ivettef365):

then you have 4x - 12 + x - 7 -------------- (x-3)(x-7)

OpenStudy (ivettef365):

now combine like terms

OpenStudy (anonymous):

|dw:1371232864645:dw|

OpenStudy (anonymous):

would that be the answer?

OpenStudy (anonymous):

invettef365 u still there?

OpenStudy (ivettef365):

yes that is correct

OpenStudy (anonymous):

ok ty hate to do this but i only got one more problem on my HW could u help me out with it?

OpenStudy (ivettef365):

no actually it is 5x - 19 -------- (x-3)(x-7)

OpenStudy (ivettef365):

sure

OpenStudy (anonymous):

ty simplify (x+1/x^2)+(3/4x)

OpenStudy (ivettef365):

ok, you have x + 1 3 ------- + -------- x^2 4x

OpenStudy (ivettef365):

what is the common denominator??

OpenStudy (anonymous):

(x^2)(4x)

OpenStudy (ivettef365):

actually it is 4x^2

OpenStudy (anonymous):

:( i hate fractions

OpenStudy (ivettef365):

because you can divide as follows: 4x^2 4x^2 ---- = x and ------ = 4x 4x x

OpenStudy (ivettef365):

sorry I meant 4x^2 ----- = 4 x^2

OpenStudy (anonymous):

its ok

OpenStudy (ivettef365):

then you have 4(x+1) + 3(x) ------------- 4x^2

OpenStudy (ivettef365):

do you understand how I got there?

OpenStudy (anonymous):

yea sort of

OpenStudy (ivettef365):

since 4x^2/x^2 = 4 I multiply 4 (x+1) and since 4x^2/4x = x I multiply 3(x)

OpenStudy (anonymous):

ok i got it

OpenStudy (ivettef365):

know multiply 4(x+1) and 3(x) what do you get

OpenStudy (anonymous):

4x+4+3x=7x+4

OpenStudy (ivettef365):

right then you have 7x +4 ------ 4x^2

OpenStudy (anonymous):

ty so much invette

OpenStudy (ivettef365):

yw :)

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