Mathematics
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OpenStudy (anonymous):
CAN SOMEONE PLLZZZZ HELP!!!!!!!!!!
1. add and simplify (x/8x)+(7x-8/8x)
2. add and simplify (4/x-7)+(1/x-3)
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OpenStudy (ivettef365):
the first problem you have
x 7x - 8
------ + --------
8x 8x
OpenStudy (ivettef365):
whta is the common denominator
OpenStudy (anonymous):
8x
OpenStudy (ivettef365):
ok then you have
x + 7x - 8
----------
8x
OpenStudy (anonymous):
ok so my answer would be |dw:1371232193752:dw|
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OpenStudy (ivettef365):
no you can do that
OpenStudy (ivettef365):
not do that
OpenStudy (ivettef365):
then you have
8x - 8
------
8x
OpenStudy (ivettef365):
you can take out the 8
8(x-1)
------
8x
OpenStudy (ivettef365):
now you can cancel the 8 and you have
x - 1
-----
x
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OpenStudy (ivettef365):
which is the same as
1 - 1/x
OpenStudy (anonymous):
ohhh ok wb #2
OpenStudy (anonymous):
what would i do ther because they dont have common denominators
OpenStudy (ivettef365):
the second problem you have
4 1
----- + -------
x-7 x-3
OpenStudy (ivettef365):
What is the common denominator ??
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OpenStudy (anonymous):
x?
OpenStudy (ivettef365):
no, actually you have to take the hold thing
so the common denominator would be
(x-7)(x-3)
OpenStudy (anonymous):
ohh
OpenStudy (ivettef365):
so now what you do is
4 (x-3) + 1 (x-7)
---------------
(x-3)(x-7)
OpenStudy (anonymous):
ok then u would have |dw:1371232713526:dw|
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OpenStudy (ivettef365):
no, you need to first multiply 4(x-3) and then 1(x-7)
OpenStudy (ivettef365):
then you have
4x - 12 + x - 7
--------------
(x-3)(x-7)
OpenStudy (ivettef365):
now combine like terms
OpenStudy (anonymous):
|dw:1371232864645:dw|
OpenStudy (anonymous):
would that be the answer?
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OpenStudy (anonymous):
invettef365 u still there?
OpenStudy (ivettef365):
yes that is correct
OpenStudy (anonymous):
ok ty hate to do this but i only got one more problem on my HW could u help me out with it?
OpenStudy (ivettef365):
no actually
it is
5x - 19
--------
(x-3)(x-7)
OpenStudy (ivettef365):
sure
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OpenStudy (anonymous):
ty
simplify (x+1/x^2)+(3/4x)
OpenStudy (ivettef365):
ok, you have
x + 1 3
------- + --------
x^2 4x
OpenStudy (ivettef365):
what is the common denominator??
OpenStudy (anonymous):
(x^2)(4x)
OpenStudy (ivettef365):
actually it is 4x^2
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OpenStudy (anonymous):
:( i hate fractions
OpenStudy (ivettef365):
because you can divide as follows:
4x^2 4x^2
---- = x and ------ = 4x
4x x
OpenStudy (ivettef365):
sorry I meant
4x^2
----- = 4
x^2
OpenStudy (anonymous):
its ok
OpenStudy (ivettef365):
then you have
4(x+1) + 3(x)
-------------
4x^2
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OpenStudy (ivettef365):
do you understand how I got there?
OpenStudy (anonymous):
yea sort of
OpenStudy (ivettef365):
since 4x^2/x^2 = 4 I multiply 4 (x+1)
and since 4x^2/4x = x I multiply 3(x)
OpenStudy (anonymous):
ok i got it
OpenStudy (ivettef365):
know multiply 4(x+1) and 3(x) what do you get
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OpenStudy (anonymous):
4x+4+3x=7x+4
OpenStudy (ivettef365):
right then you have
7x +4
------
4x^2
OpenStudy (anonymous):
ty so much invette
OpenStudy (ivettef365):
yw :)