Please help! Let theta be an angle in quad. 2 such that sin theta = 3/5. Find the exact values of sec theta and tan theta. Sec theta=? Tan theta=?
First let us get the hypotenuse = √{(-5)²+3²} =√34 so cos Ө = -5/√34 since Ө is quadrant II angle sin Ө = 3/√34 sec Ө is reciprocal of cos Ө = √34/5 and tan Ө = -3/5
the hypot is no sqrt34
consider: sin^2 + cos^2 = 1
don't forget the most famousest right triangle of the all the granddaddy right triangle, the mother of all right triangles
a square?
in fact it is so famous, that it leaves its imprint on any other right triangle with integer sides
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all i can think of is: oh no, there goes tokyo, go go godzilla; which then leads me into , everybody was kungfu fighting
mkty was on a good track except that sin is defined as over/hypot 3 is a leg and 5 is the hypot
and therefore the other side is 4, as pictured now take your ratios from that one
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