Question

what is the solution set for the equation x^2-3x=10

Answer 1

Subtract 10 to the left side.
Then try factoring the left side.

Answer 2

http://www.mathsisfun.com/algebra/quadratic-equation.html

Answer 3

x^2 - 3x=10
x^2-3x-10=0
(x-5)(x+2)=0

Answer 4

x^2 - 3x = 10
x^2 - 3x - 10 = 0
(x - 5)(x + 2) = 0
x - 5 = 0
x = 5 + 0
x = 5
and x + 2 = 0
x = -2 + 0
x = -2
answer : x = 5 and x = -2

Answer 5

Note that this is called the zero product rule, where we equate 0 to something like (x-5)(x+2), and thus from here we can conclude that both sides are equal to zero. We can't do this if for example (x-3)(x-4)=5 though :) have a nice day!