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What is the sum of the arithmetic sequence 3, 11, 19 ..., if there are 26 terms?
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common difference is 8
first term is 3
3x + 8x (x - 1)/2 x = the number of terms so 26.
there are a few ways to approach this, either way you have to determine the a1 + d(n-1) setup the 26th term is of course: 3 + 8(25) 26 [3+3+8(25)] --------------- 2
26 terms first = 3 last = 3+8(25) first + last = 3+3+8(25) = 206 26(206) = 5356 and half of that is ....
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2,678! Thank You! :)
it gets easier with practice :) your welcome
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