Question

A large watermelon weighs 20 kg with 98% of its weight being water. It is left to stand in the sun and some of
the water evaporates so that now only 95% of its weight is water. What is its reduced weight?
(A) 17 kg (B) 19.4 kg (C) 10 kg (D) 8 kg (E) None of these.

Answer 1

a

Answer 2

amt of water before drying: 0.98*20 = 19.6 kg
non-water weight of the melon: 0.4 kg

After drying:
Let weight be "x".
Equation:
The non-water material in the melon is now 5% of its weight.
0.05x = 0.4 kg
x = 8 kg

Answer 3

Ok Then ?

Answer 4

@oldrin.bataku

Answer 5

oops sorry thanks

Answer 6

Anytime.