The number N of state and federal inmates in millions during year x, where x > can be approximated by the following formula. N=0.05x-99.20 Determine the year in which there were 1.1 million inmates. Can someone show me the steps?
N=0.05x-99.20 N is the number of imates, is 1.1 1.1 = 0.05x - 99.20 solve for x
oh i left off an important peice the year 2002 (is x is less > or equal to)
we can use that after you determine x id suggest you add and then divide .....
i assume x is the number of years after 2002, so 2002+x would most likely be the final results
yes it is
if the decimals are disturbing, move all decimals to the right by 2 1.1 = 0.05x - 99.20 110 = 5x - 9920
how do you get the 1.1?
by reading the question ...
N is the number of inmates, when the number of inmates is 1.1 ....
N=0.05x-99.20 N is the number of inmates, is 1.1 ... replace N by 1.1 1.1 = 0.05x - 99.20 , multiply both sides by 100 for convenience (not required, but nice nonetheless) 110 = 5x - 9920
ok thank you
good lcuk
*luck even :)
thanks
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