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Mathematics 19 Online
OpenStudy (ja1):

I need some checking done, it's my first equation like this. Will put up shortly.

OpenStudy (nincompoop):

you're slow, dude

OpenStudy (jdoe0001):

hehe

OpenStudy (ja1):

\[H(t) = -16t ^{2} + 16t + 32\] \[0 = -16t ^{2} + 16t + 32\] A = -16 B = 16 C = 32 \[\frac{ -16 }{ 2(-16) }\] \[\frac{ -16 }{ -32 }\] \[\frac{ 1 }{ 2 }\] 0.5 \[H(0.5) = -16(0.5)^{2} + 16(0.5) + 32\] \[H(0.5) = -16(0.25) + 16(0.5) + 32\] \[H(0.5) = -4 + 8 + 32\] \[H(0.5) = 36\] \[(0.5,36)\] Projectile will reach 36 feet in 0.5 seconds. Is this right?

OpenStudy (ja1):

Slow...pfft...

OpenStudy (nincompoop):

seems legit

OpenStudy (ja1):

Well when you put it that way.... ;)

OpenStudy (ja1):

That's all I needed to know, I like checking my newly found knowledge before diving into the exam.

OpenStudy (ja1):

Anyone see anything wrong?

OpenStudy (nincompoop):

not in that problem. try some more, this time something that it's easy

OpenStudy (ja1):

Well yes, I have tried others it's just this was the easiest one to write out :3

OpenStudy (ja1):

Quadratics fun....

OpenStudy (jdoe0001):

am I wrong or you should have gotten 2 answers from the quadratic?

OpenStudy (ja1):

Yes but that one was the objective in this problem

OpenStudy (jdoe0001):

I seem to get 2304 for the discriminant, whose root is 48

OpenStudy (jdoe0001):

the procedure looks fine otherwise

OpenStudy (ja1):

Yay :D time for the examz...

OpenStudy (ja1):

http://instantcsi.com/

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