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Find sinA is b = 4, c = 4√5
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I'm not asking for the answer I'm asking for what the first thing I should do is
you have a diagram?
What diagram?
ahemm, I think it's meant to mean b = opp side, c = hyp
lol how are we suppose to know that?
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hehe
a would be oppossite then?
Okay it says For triangle ABC, angle C is a right angle. Find the value of the trig function indicated. Find sinA if b = 4, c = 4√5
$$ sin(a) = \cfrac{4}{4\sqrt{5}} \implies \cfrac{opp}{hyp} $$
Soo c is the opposite
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looks wrong to me
hehe
right, if C is \(90^o\) then "c" is the hypotenuse
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