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Mathematics 7 Online
OpenStudy (anonymous):

Use basic identities to simplify the expression. (tan(θ))/(cot(θ))

OpenStudy (zzr0ck3r):

(a/b)/(b/a) = (a/b)(a/b)

OpenStudy (anonymous):

a=tan b=cot?

OpenStudy (zzr0ck3r):

a = sinx, b = cosx (sinx/cosx)/(cosx/sinx) = sinx*sinx/cosx*cosx = sin^2(x)/cos^2(x)

OpenStudy (zzr0ck3r):

sin^2(x) + cos^2(x) = 1 divide everything by cos^2(x) and you have (sin^2(x)/cos^2(x)) = sec^2(x) -1

OpenStudy (anonymous):

what is sec^2(x)-1 equal too because that is not an option?

OpenStudy (anonymous):

options are: sec2θ sin θ tan2θ cos3θ

OpenStudy (zzr0ck3r):

many things, what are the options

OpenStudy (zzr0ck3r):

tan^2(x) = sin^x*sin^x/cos^x*cos^2x

OpenStudy (anonymous):

tank you!

OpenStudy (zzr0ck3r):

tan^2(x) = sin^2xsin^2x/cos^2x*cos^2x

OpenStudy (anonymous):

thank*

OpenStudy (zzr0ck3r):

np

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