Question

y=2/(|x|+1)-x^2/7

How do you find the intervals on which the function is continuous?

Answer 1

is that:\[\bf y= \frac{2}{|x|+1}-\frac{x^2}{7}\]?
@wesdg1978

Answer 2

is this ever discontinuous?

Answer 3

so the answer is R

Answer 4

@genius12 yes, that's it

Answer 5

If it's continuous everywhere, how would I know that?

Answer 6

do you ever have the chance to divide by 0?

Answer 7

I don't see anyway to make the denominator zero.

Answer 8

note, if the absolute value was not there, it would be discontinuous at -1