Question

Mathematics Quiz #2 :

Get ready.

Total Questions :10

Marks for correct answer : 4
Marks for wrong answer : -1

The first who answers will be awarded with +4.
The second who answers with a short hint of the soln will also be awarded +4.

Only 2 answers will be considered.

Are you guys ready?

[part 2]

Answer 1

c'mon!

Answer 2

:-p

Answer 3

Solve the equation : \((6-x)^4 + (8-x)^4 = 16\)

Answer 4

use wolfram, lol

Answer 5

Oh... Don't cheat urself and others PLEASE

Answer 6

okay fine :-(

Answer 7

LOL

Answer 8

(6,0) (8,0)

Answer 9

@chris00 , give me a hint...

Answer 10

graph it and find the roots

Answer 11

Not proper method. I guess u used wolfram or any other source?

Answer 12

graph (6-x)^4+(8-x)^4-16=0

Answer 13

my calculator

Answer 14

okay, I just lost it.... LOL

Answer 15

thats a proper source.

Answer 16

lol Your answer will not be considered. [AS you used calculator]

Yes @SharpEdge , changing the variable : +4

Answer 17

rules should be more explicit. haha

Answer 18

One more chance left. Oldrin, don't type whole soln, just give a hint...

Answer 19

1 minute more...

Answer 20

Time is up.

Answer 21

Points table :

@SharpEdge : 14
@oldrin.bataku : 14
@terenzreignz : 12
@johnweldon1993 : 4
@chris00 : 1

Answer 22

Next question : 7 , be ready

Answer 23

least i'm in the positives

Answer 24

So much for four points all, you only gave @oldrin.bataku 2 points...

Answer 25

It's good! Just post the questions faster I have a test tomorrow morning and it's almost 12 ;-)

Answer 26

Okay..

Solve : \(x^2 - 5|x| + 6 = 0 \)

Answer 27

+/- 1
+/- 6

Answer 28

$$u=|x|\\u^2-5u+6=0\\u=3,2\\x=-3,-2,2,3$$

Answer 29

x=2,3

Answer 30

No^ (-1) @terenzreignz

Answer 31

crud. :D
me too much of in a hurry

Answer 32

@oldrin.bataku : +4

@RadEn : (-1)

Answer 33

that was mighty quick terenz.

Answer 34

too quick. oh well :D

Answer 35

ah, +-2, +-3 i mean :)

Answer 36

New thread?

Answer 37

I was TJ.... still am, really XD

Answer 38

No need for a new thread yet... btw nice try @RadEn ;-) hehe

Answer 39

Yes... @SharpEdge : +4

@RadEn [ U had to post the hint too :( ]

Answer 40

if x > 0, then x = 2,3
if x < 0, then x = -2,-3

Answer 41

Points table :

@oldrin.bataku : 18
@SharpEdge : 18
@terenzreignz : 11
@johnweldon1993 : 4
@chris00 : 1
@RadEn : -1

Answer 42

RadEn, sorry a bit late

:(

Answer 43

haha, nope :)

Answer 44

can I enter and try?

Answer 45

entry fee is 5 dollars

Answer 46

Better question would be who can stop you @karatechopper :D

Answer 47

Yep KC. You're welcome. But read the rules first... :)

Answer 48

I give u a high five. @chris00

Answer 49

Question no. 8 :

Solve the equation : |x-|4-x||- 2x = 4

Answer 50

that will do

Answer 51

Suggestion : Don't be in hurry (@terenzreignz ) :P

Answer 52

(0,0)

Answer 53

Post the hint too. + Answer

Answer 54

$$x=0$$

Answer 55

@chris00 , did u mean 0 as the answer?

Answer 56

yes

Answer 57

@chris00 : + 4

@SharpEdge : -1

@oldrin.bataku [give hint, if u want +4] :)

Answer 58

I got 0

Answer 59

KC hint please..

Answer 60

$$|x-4+x|-2x=4\\2x-4-2x=4\\-4=4\\|x-x+4|-2x=4\\4-2x=4\\x=0$$

Answer 61

Time up for all. @oldrin.bataku : +4

Points table :

@oldrin.bataku : 22
@SharpEdge : 17
@terenzreignz : 11
@johnweldon1993 : 4
@chris00 : 5
@RadEn : -1

Answer 62

conflicting answers... interesting :D

Answer 63

@karatechopper , u have to give hint also... :(

Answer 64

no conflicting answers here...:-)

Answer 65

ohh I get it now..

Answer 66

Be ready for second last question...

Answer 67

oh wait, sharpedge got -1 nvm

Answer 68

its k. Don't put me in points I'm just wanting to learn.

Answer 69

Good spirit KC. Loved it

Answer 70

hahahaha gd one.

Answer 71

no, I thought you got it right, and hence, I thought we got conflicting answers

Answer 72

ah, algebra again.. where is these : combinatoric or trigono/geo or others hahaha

Answer 73

Possibly in the next few quizzes to come, if ever

Answer 74

yes more!! do the last questions c'mon :-)

Answer 75

How many number of 6 digits can be formed with the digits 1,2,3,4,5,6 in which 5 always occur in ten's place ?

@RadEn : combinatorics :)

Answer 76

This is the second last Sharp.

Answer 77

6^5

Answer 78

Principle of Multiplication?

Answer 79

@SharpEdge : +4

@terenzreignz : Nopes.. (-1)

Answer 80

One more chance left..

Answer 81

You could have mentioned that no digits may be repeated

Answer 82

$$5\ \_\ \_\ \_\ \_\ \_$$With \(5\) free spots each having one less digit we get \(5\times4\times3\times2\times1=120\)

Answer 83

If u repeat any digit then one digit will be left. So no need to mention that.

Answer 84

one less digit possibility than the previous

Answer 85

@oldrin.bataku : +4

Answer 86

You didn't say you had to use all the digits neither... c'mon @mathslover a little clarity next time?

Answer 87

lol Okay... Sorry :( :)

Answer 88

At the very least, retract that -1... (pretty please)

Answer 89

lol

Answer 90

assert urself terenz.

Answer 91

I need ice cream.

Answer 92

@terenzreignz has a point... I almost said \(6^5\) then I saw the other guy's answer accepted and knew immediately every digit had to be used

Answer 93

@oldrin.bataku : 26
@SharpEdge : 21
@terenzreignz : 11 [Regreted.]
@johnweldon1993 : 4
@chris00 : 5
@RadEn : -1