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Find the distance from point A (4, 1 and 1 half) to point B (2 and 2 thirds, -3)
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\(\large A (4, \ \ 1\frac{1}{2})\) \(\large B (2\frac{2}{3} , -3)\)
like this ?
yes
first convert the improper fractions.
you knw how to convert a 'mixed fraction' to an 'improper fractions' ?
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3/2? and 5/3
\(1 \frac{1}{2} = 1 + \frac{1}{2} = \frac{3}{2}\)
\(2\frac{2}{3} = 2 + \frac{2}{3} = \frac{\color{red}{8}}{3}\)
right you multiply not add them ok
ha
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use the distance formula now
so subtract -3 and 3/2?
yes !
\(A (4, \ \frac{3}{2})\) \(B (\frac{8}{3}, -3)\)
how 2.5 ?
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