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Mathematics 8 Online
OpenStudy (anonymous):

can anyone help me with this secant length question.

OpenStudy (anonymous):

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OpenStudy (anonymous):

it would be (10)4=(3+x)3 right?

OpenStudy (anonymous):

but then whats next

OpenStudy (anonymous):

no wait it would be 40= (3+x)x

OpenStudy (anonymous):

40=3x-x^2

ganeshie8 (ganeshie8):

how did + became -

OpenStudy (anonymous):

typo... whoops

ganeshie8 (ganeshie8):

ok... you're doing good :) keep going...

OpenStudy (anonymous):

40=3x+x^2

OpenStudy (anonymous):

0=x^2+3x-40

OpenStudy (anonymous):

(x ) (x ) how do i factor it

ganeshie8 (ganeshie8):

list factors of -40, that add upto 3

OpenStudy (anonymous):

oh -5 and 8

ganeshie8 (ganeshie8):

yes

OpenStudy (anonymous):

so x=5 or x=-8

OpenStudy (anonymous):

but it cant be negative so its 5

ganeshie8 (ganeshie8):

brilliant !!!!

OpenStudy (anonymous):

Thanks so much :)

ganeshie8 (ganeshie8):

np :)

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