Question

the line passes through the orgin and has a slope of 4. what is the equation of the line that is parallel to the first line and passes through the point (1,-2)

Answer 1

(0,0) and m=4
Use
\[\Huge y-y_1=m(x-x_1)\]
y1=0
x1=0

Answer 2

Similarly you have points and m in 2nd case as well

Answer 3

Let the equation of the original line be y=mx+c where m is the slope of the line and(x,y) is the required point....
now since the line passes through origin....so origin satisfies the equation of the line...
0=m(0)+c
c=0
thus we get y=mx
in this case m=4
thus eqution of original line is y=4x
.........
now we have the find the equation of such a line which is parallel to the above line .....(parallel lines have same slope)
so the slope of this line is also equal to 4
secondly it passes through (1,-2)...therefore
-2=4(1)+c
-2-4=c
c=-6
thus the final equation of the new line is y=4x-6...(in slope form)

Answer 4

You are not supposed to give out the answer but guide the asker to it.

Answer 5

sorry.....

Answer 6

thanks nitz anyway so much

Answer 7

u are welcome..