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Given ∆ABC ~ ∆JKL, find the ratio of the perimeters of ∆ABC to ∆JKL. how do i do this O.O plz help
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|dw:1371481018573:dw|
hint :- ratio of perimeters wil be same as ratio of sides.
|dw:1371482102098:dw|
soo18 to the 3rd power * 12 to the 3rd power ???????????
lol from where u getting 3rd powers ?
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its a triangle lol idk xD
i hate triangles!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
lol you're me when i was in my 11th grade lol
its simply \(\frac{12}{8}\)
lol thts jus it im doin this crap 9th - 11th gahhhh
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you're in 9th grade ?
well in between 9th and 10th lol this is a summer course
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