Question

Find the x-intercept(s):
4x^2-3y^2+2xy-12=0

Answer 1

Do I just set the y=0 and solve from there?

Answer 2

I got \[\pm \sqrt{3}\]

Answer 3

Yes, just set y=0

Answer 4

\[4x^2-3y^2+2xy-12=0\]

Answer 5

Thanks!

Answer 6

yes thats correct method

Answer 7

So your answer is correct

Answer 8

4x^2 = 12
z^2 = 3

Answer 9

* x^2 lol

Answer 10

Thanks.